Question

Consider the following array:

int[,] numbers = new int[3, 2] { { 2, 1 }, { 3, 4 }, { 6, 5 } };

I would like to use LINQ to construct an IEnumerable with numbers 2, 1, 3, 4, 6, 5.

What would be the best way to do so?

Answer 1

How about:

Enumerable
    .Range(0,numbers.GetUpperBound(0)+1)
    .SelectMany(x => Enumerable.Range(0,numbers.GetUpperBound(1)+1)
    .Select (y =>numbers[x,y] ));

or to neaten up.

var xLimit=Enumerable.Range(0,numbers.GetUpperBound(0)+1);
var yLimit=Enumerable.Range(0,numbers.GetUpperBound(1)+1);
var result = xLimit.SelectMany(x=> yLimit.Select(y => numbers[x,y]));

EDIT Revised Question….

var result = array.SelectMany(x => x.C);