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Home/ Questions/Q 951139
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:41:02+00:00 2026-05-15T23:41:02+00:00

Consider the following class: class Foo { enum Flags {Bar, Baz, Bax}; template<Flags, class

  • 0

Consider the following class:

class Foo
{
  enum Flags {Bar, Baz, Bax};

  template<Flags, class = void> struct Internal;

  template<class unused> struct Internal<Bar, unused> {/* ... */};
  template<class unused> struct Internal<Baz, unused> {/* ... */};
  template<class unused> struct Internal<Bax, unused> {/* ... */};
};

The class outline above compiles and functions as expected when tested on VC++ 2010 and Comeau C++. However, when Foo is made into a template itself, the above snippet breaks under VC++ 2010.

For example, the following snippet:

template<class> class Foo
{
  // Same contents as the original non-templated Foo.
};

Yields the following error class:

C2754: 'Foo<<unnamed-symbol>>::Internal<Bar,unused>' : a partial specialization cannot have a dependent non-type template parameter
C2754: 'Foo<<unnamed-symbol>>::Internal<Baz,unused>' : a partial specialization cannot have a dependent non-type template parameter
C2754: 'Foo<<unnamed-symbol>>::Internal<Bax,unused>' : a partial specialization cannot have a dependent non-type template parameter

  1. Can someone explain what is going on here in plain English?
  2. How can I fix this (i.e., keep internal pseudo-explicit specializations in a templated Foo) on VC++ 2010?
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  1. Editorial Team
    Editorial Team
    2026-05-15T23:41:03+00:00Added an answer on May 15, 2026 at 11:41 pm

    How can I fix this (i.e., keep internal pseudo-explicit specializations in a templated Foo) on VC++ 2010?

    You can make the enumeration type non-dependent by declaring it in a non-template base class (C++03 made nested classes dependent in #108 but that doesn’t include enumeration, but even if, such code would still be legal).

    struct FooBase { 
      enum Flags {Bar, Baz, Bax};
    };
    
    template<class> class Foo : public FooBase {
      template< ::FooBase::Flags, class = void > struct Internal;
      // same other stuff ...
    };
    

    The “error class” link already gives a description of the intended cases where the error should be risen. The error thinks that all dependent types are forbidden, but in fact this is what the Standard says:

    The type of a template parameter corresponding to a specialized non-type argument shall not be dependent on a parameter of the specialization.

    So even if the name Flags would be somehow dependent, that wouldn’t make it ill-formed as long as it doesn’t depend on a parameter of the specialization like in the example of your “error class” link.

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