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Home/ Questions/Q 8431119
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T05:46:15+00:00 2026-06-10T05:46:15+00:00

Consider the following piece of operational Haskell code : Code A describeList :: [a]

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Consider the following piece of operational Haskell code :

Code A

describeList :: [a] -> String
describeList xs = "The list is " ++ what xs
    where what [] = "empty."
          what [x] = "a singleton list."
          what xs = "a longer list."

which is a snippet taken from Syntax in Functions. Now suppose that we start off with the following piece of badly indented and non-operational Haskell code :

Code B

describeList :: [a] -> String
describeList xs = "The list is " ++ what xs
where what [] = "empty."
what [x] = "a singleton list."
what xs = "a longer list."

Then is there any tool which can take the badly indented code (Code B) and correctly indents it so as to yield operational code (Code A)?

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  1. Editorial Team
    Editorial Team
    2026-06-10T05:46:17+00:00Added an answer on June 10, 2026 at 5:46 am

    This is next to impossible to do (and I’m writing this as a response because I’ve been looking for a tool myself that can do this) because unindented Haskell code can be very ambiguous.

    Consider the code:

    describeList :: [a] -> String
    describeList xs = "The list is " ++ what xs
      where what [] = "empty."
            what [x] = "a singleton list."
            what xs = "a longer list."
    

    Let’s also consider some alternative, also valid, interpretations:

     -- top-level function "what" without type signature
    describeList :: [a] -> String
    describeList xs = "The list is " ++ what xs
      where what [] = "empty."
    what [x] = "a singleton list."
    what xs = "a longer list."
    
    -- same as above
    describeList :: [a] -> String
    describeList xs = "The list is " ++ what xs
      where what [] = "empty."
            what [x] = "a singleton list."
    what xs = "a longer list."
    
    -- There might be a `data String a b`, so `String describeList xs` is
    -- a type. The clause then becomes a guarded pattern match (similar to 
    -- `let bar :: Int = read "1"`) with scoped type variables. The `where`
    -- clause is still syntactically valid. The whole thing might not compile,
    -- but a syntax tool can't know that.
    describeList :: [a] -> String
                           describeList xs = "The list is " ++ what xs
      where what [] = "empty."
            what [x] = "a singleton list."
    what xs = "a longer list."
    
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