Consider the following script:
#!/bin/bash
num=0
cat file | while read line; do
echo "$line"
lines[$num]="$line"
((num++))
echo "num = $num"
done
echo "end num = $num"
i=0
while [ $i -lt $num ]; do
echo "${lines[$i]}"
((i++))
done
Normally, it should read the file line by line, store the result in an array, then go through the array and print it line by line. The problem is that the variable $num resets somehow after the first loop exits. The output of this script for me is the following (using a file with some random garbage in it):
dsfkljhhsdfsdfshdjkfgd
num = 1
fdfgdfgdfg
num = 2
dfgdfgdfgdfg
num = 3
dfgdfgdfgdfgdfg
num = 4
dfgdfgdfgdfgdfgd
num = 5
fgdfgdfgdfg
num = 6
dfgdfgdfgdfg
num = 7
dfgdfgdfgdfgdfg
num = 8
dfgdfgdfgdfg
num = 9
dfgdfgdgdgdg
num = 10
dfgdffgdgdgdg
num = 11
end num = 0
Why is this? How do I achieve to remember the variable? I am using bash 3.1.17 on SUSE Linux 10.
Why? It’s because this:
runs the
whilestatement in a separate process, with its own environment, not touching the parent environment. You’ll find, similarly, that thelinesarray is not there either.The following simplified script shows this in action:
The output of that script is:
because the setting of the variable to
999is done in the subprocess.Bottom line, if you want information to be reflected in the current process (the script), you’ll need to do the work in the script or find some other way to get the information out of the sub-process.
If you use input redirection rather than starting a sub-process pipeline, it should work as you want. That’s because the
whilebit is then done in the context of the current process rather than a separate process in a pipeline. For example:will produce:
For your specific case, replace:
with: