Question

Consider this code:

int x = 17;
int y = 013;
System.out.println("x+y = " + x + y);

When I run this code I get the output 1711. Can anybody tell me how do I get 1711?

Answer 1

The 17 is there directly.

013 is an octal constant equal to 11 in decimal.

013 = 1*8 + 3*1 = 8 + 3 = 11

When added together after a string, they are concatenated as strings, not added as numbers.

I think what you want is:

int x = 17;
int y = 013;
int z = x + y;

System.out.println("x+y = " + z);

or

System.out.println("x+y = " + (x + y));

Which will be a better result.