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Home/ Questions/Q 7861411
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T22:43:13+00:00 2026-06-02T22:43:13+00:00

Consider this code: OperatorTable addOperator(:, 2) : := method(value, list(self, value) ) hash :=

  • 0

Consider this code:

OperatorTable addOperator(":", 2)

: := method(value,
  list(self, value)
)

hash := "key": "value"
hash println

The return should be list(key, value), and when using this in the Io REPL that is exactly the return value. When using the interpreter (as in io somefile.io) the value returned is value. After some inspection the difference is here:

# In the REPL
OperatorTable addOperator(":", 2)
message("k" : "v") # => "k" :("v")

# Via the Interpreter
OperatorTable addOperator(":", 2)
message("k" : "v") # => "k" : "v"

Why is this happening?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T22:43:14+00:00Added an answer on June 2, 2026 at 10:43 pm

    File execution happens in these stages:

    • load file
    • replace operators based on the current operator table
    • execute contents

    So operator to message conversion only happens when the file is initially loaded in stage 2.
    When the operator registration code is executed in stage 3. this has already happened,
    thus the operator has no effect.

    You can set the order which files get loaded manually and put the operator definition in the first file loaded.
    Having a file called operators.io for example which includes all operator definitions loaded before the files that use them.

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