Consider this example
def dump(value):
print value
items = []
for i in range(0, 2):
items.append(lambda: dump(i))
for item in items:
item()
output:
1
1
how can i get:
0
1
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You can use a parameter with a default value on the lambda:
This works because the default value is evaluated when the function is defined, not when it is called.