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Home/ Questions/Q 924549
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:22:18+00:00 2026-05-15T19:22:18+00:00

Consider this example: var x = 0; for (var i = 0; i <

  • 0

Consider this example:

var x = 0;

for (var i = 0; i < 100; i++ )
{
    for (var a = i+1; a < 100; a++)
        x += 1;
}

When printing x we always get 4950. What about if I want to parallelise this?

This is what I come up with

Parallel.For(0, 100, i => Parallel.For(i + 1, 100, a => { x += 1; }));

However this does Not print 4950 each time I run it. Why?

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:22:19+00:00Added an answer on May 15, 2026 at 7:22 pm

    Parallel Extensions helps you with task creation, allocation, running and rendezvous, in a near-imperative syntax. What it doesn’t do is take care of every kind of thread safety (one of the pitfalls). You are trying to make parallel threads simultaneously update a single shared variable. To do anything like this correctly, you have to introduce e.g. locking.

    I’m not sure what you’re trying to do. I assume your code is just a placeholder or experiment. Parallelization is only suitable when you can isolate your different pieces of work; not when you constantly have to rendezvous with shared data.

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