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Home/ Questions/Q 6131107
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:56:08+00:00 2026-05-23T16:56:08+00:00

Consider this piece of code: Set<String> mySet = new HashSet<String>(){{add(foo);add(boo);}}; or for the HashMap

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Consider this piece of code:

Set<String> mySet = new HashSet<String>(){{add("foo");add("boo");}};

or for the HashMap:

Map<String,String> myMap = new HashMap<String,String>(){{put("foo","bar");put("boo","jar");}};

Pros are simply to find: less lines of code, conciseness. But what are the cons?

UPD: The question is not only about sets, but about all types of collections, added Map to illustrate this.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:56:09+00:00Added an answer on May 23, 2026 at 4:56 pm

    When you do that, you are creating an anonymous subclass of HashSet, which means you are unnecessarily polluting your code base with classes that don’t do anything new.

    How about this instead?

    Set<String> set = new HashSet<String>(Arrays.asList("foo", "bar"));
    

    Or alternatively, use Guava‘s Sets class. It has factory methods to initialize different kinds of sets:

    Set<String> set = Sets.newHashSet("foo", "bar");
    

    With Maps it’s trickier, but you can use ImmutableMap:

    Map<String,String> myMap = 
        ImmutableMap.of("foo","bar","boo","jar");
    

    or (mutable version)

    Map<String,String> myMutableMap =
            Maps.newHashMap(ImmutableMap.of("foo","bar","boo","jar"));
    

    Without external libraries, you can still initialize a Map with a single entry:

    Map<String,String> myMap = new HashMap<String, String>(
        Collections.singleTonMap("foo","bar")
    );
    

    but that be one ugly beast, if you ask me.


    UPD: The question is not only about sets, but about all types of
    collections, added Map to illustrate this.

    Guava has several Factory classes like this:

    Sets, Maps, Lists, Multimaps, Multisets, Ranges

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