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Home/ Questions/Q 929445
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T20:10:21+00:00 2026-05-15T20:10:21+00:00

const unsigned int omode = cimg::exception_mode(); cimg::exception_mode() = 0; Never see this kinda syntax

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  const unsigned int omode = cimg::exception_mode();
  cimg::exception_mode() = 0;

Never see this kinda syntax before.

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  1. Editorial Team
    Editorial Team
    2026-05-15T20:10:22+00:00Added an answer on May 15, 2026 at 8:10 pm

    exception mode might be returning a reference, and it is being set to 0. For example:

    unsigned int& exception_mode() { return mode; };
    

    So, the second line would be equivalent to:

    void set_exception_mode( uint v ) { mode = v; };
    

    BTW, it is really ugly! I would avoid this kinda syntax as much as I could.

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