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Home/ Questions/Q 9215489
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T02:12:57+00:00 2026-06-18T02:12:57+00:00

Could anyone explain what is wrong with this code: public class Base { static

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Could anyone explain what is wrong with this code:

    public class Base {


    static {
        i = 1;
        System.out.println("[Base]after static init block i=" + i);// LINE 1
        System.out.println("*************************************");
        System.out.println();
    }
    static int i;



    public static void main(String[] args) {
        System.out.println(Base.i);
    }
}

If I comment LINE 1 – everything is OK and Base.main method prints “1”.
If LINE 1 – is not commented, got compile time error: “illegal forward reference”.
So, as i understand in static init block I can set value for i, but not read. Could anyone explain why?

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  1. Editorial Team
    Editorial Team
    2026-06-18T02:12:58+00:00Added an answer on June 18, 2026 at 2:12 am

    This is because of the restrictions on the use of Fields during Initialization. In particular, the use of static fields inside a static initialization block before the line on which they are declared can only be on the left hand side of an expression (i.e. an assignment), unless they are fully qualified (in your case Base.i).

    So for example: if you insert int j = i; right after i = 1; you would get the same error.

    The obvious way to solve the issue is to declare static int i; before the static initialization block.

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