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Home/ Questions/Q 6003349
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:06:31+00:00 2026-05-23T01:06:31+00:00

Current Code I have two functions as f1::Int->Int->Int f1 a b | a==1 &&

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Current Code

I have two functions as

f1::Int->Int->Int
f1 a b | a==1 &&  b==1 = 1
       | otherwise = 0

applying this function to a [Int] by a another function

f2::[Int]->[Int]->[Int]
f2 a b = map f1 a b

Error

Type error in application
*** Expression     : map f1 c d
*** Term           : map
*** Type           : (e -> f) -> [e] -> [f]
*** Does not match : a -> b -> c -> d

Conclution

actually what i requied is to apply the f1 which perform to a Int to a [Int] using f2
is this problem can solved in higher order functions ? or any other method ? … or how can i transform f2 to be a higher order function to take f1 ?

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T01:06:31+00:00Added an answer on May 23, 2026 at 1:06 am

    If you want to apply the function to two list you need a different function, namely zipWith.

    f2 a b = zipWith f1 a b
    
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