Question

def c():
    yield 222
    yield 333

a=[1,2,3,4]
b=iter(c,333)
print a,b
for i in b:
    print i

how can i get it.

Answer 1

You need to provide the function (which will return the next value) to your iter() call. In your case, that’s c().next rather than c.

This snippet below works as expected by producing all the yielded values up to, but exclusive of, the terminating value.

def generator():
    yield 1
    yield 2
    yield 3
    yield -1

sequence = iter (generator().next, -1)
print sequence
for value in sequence:
    print value

The output of that is:

pax> python prog1.py
    <callable-iterator object at 0xb77dd6ac>
    1
    2
    3
pax> _