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Home/ Questions/Q 7842205
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T16:16:00+00:00 2026-06-02T16:16:00+00:00

def change(s): s = s + ! word = holiday change(word) print word how

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def change(s):
    s = s + "!"


word = "holiday"
change(word)    
print word

how come the output of this is “holiday” instead of “holiday!”? Is it because the 3 line of codes are outside the function? If so, why would it matter if it’s outside the function since it’s after the change function?

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  1. Editorial Team
    Editorial Team
    2026-06-02T16:16:01+00:00Added an answer on June 2, 2026 at 4:16 pm

    Try this:

    def change(s):
        return s + "!"
    

    Use it like this:

    word = 'holiday'
    print change(word)
    

    Or like this:

    word = 'holiday'
    word = change(word)
    print word
    

    Be aware that any modifications you do to a parameter string inside a function will not be seen outside the function, as the s parameter in the function is local to the scope of the function, and any changes you do (like in the code in the question) will only be visible inside the function, not outside. All function parameters in Python are passed by value.

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