Question

def funct():
    x = 4
    action = (lambda n: x ** n)
    return action

x = funct()
print(x(2)) # prints 16

… I don’t quite understand why 2 is assigned to n automatically?

Answer 1

n is the argument of the anonymous function returned by funct. An exactly equivalent defintion of funct is

def funct():
    x = 4
    def action(n):
        return x ** n
    return action

Does this form make any more sense?