def funct():
x = 4
action = (lambda n: x ** n)
return action
x = funct()
print(x(2)) # prints 16
… I don’t quite understand why 2 is assigned to n automatically?
def funct(): x = 4 action = (lambda n: x ** n) return action
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def funct():
x = 4
action = (lambda n: x ** n)
return action
x = funct()
print(x(2)) # prints 16
… I don’t quite understand why 2 is assigned to n automatically?
nis the argument of the anonymous function returned byfunct. An exactly equivalent defintion offunctisDoes this form make any more sense?