Question

def myFunc( a, b ):
  def innerFunc( c ):
    print c
  innerFunc( 2 )
  print a, b

How can I access the inner function directly? I want the object/address of that function in the format

<function innerFunc at 0xa0d5fb4>

I tried with myFunc._getattr_( ‘innerFunc’ ) but that didn’t work.

Answer 1

what you could do is either return the function or attach it to its parent when called …

>>> def myFunc( a, b ):
...     def innerFunc( c ):
...         print c
...     innerFunc( 2 )
...     myFunc.innerFunc = innerFunc
...     print a, b
...
>>>
>>> myFunc(1,2)
2
1 2
>>> myFunc.innerFunc(3)
3
>>> 

though apparently you can access the source code using a special attribute, that function objects have … myFunc.func_code though this seems to be accessing some serious stuff

>>> help(myFunc.func_code)
 Help on code object:
 class code(object)
  |  code(argcount, nlocals, stacksize, flags, codestring, constants, names,
  |        varnames, filename, name, firstlineno, lnotab[, freevars[, cellvars]])
  |  
  |  Create a code object.  Not for the faint of heart.
  |