Question

def myfunc(a,b=2):
    print("Called with", a, b)
    return
p1 = functools.partial(myfunc, b=4)
p1("foobar", 4)

Why do I get a syntax error when I run that last line? It works if i do: myfunc("foobar", 4)

Answer 1

‘partial’ already sets ‘b’ to 4; if you want another value you should explicitely set parameter ‘b’:

>>> p1("foobar")
('Called with', 'foobar', 4)

>>> p1("foobar", b=5)
('Called with', 'foobar', 5)