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Home/ Questions/Q 7604923
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T00:02:16+00:00 2026-05-31T00:02:16+00:00

def tointervals(tlist): count=0 for i in tlist: if count == 0: count = count

  • 0
def tointervals(tlist):
      count=0
      for i in tlist:
        if count == 0:
          count = count + 1
          yield 0
        else:
          count = count + 1
          yield i - tlist[count -2]

I test it like so:

In [272]: list(tointervals([1,2,3,4,10]))
Out[272]: [0, 1, 1, 1, 6]

Great, that’s exactly what I was looking for

But I want to do it in a more functional way (I’m mostly using Scala)

I’m terminally confused about this, mainly due to unfamiliarity with Python. The closest I’ve gotten before giving up in terminal confusion is this.

In [292]: reduce(lambda x,y: (x[0] + [y - x[0][x[1]] ],x[1]+1), [1,2,3,4,10], ([0],0))
Out[292]: ([0, 1, 1, 2, 2, 8], 5)

Which is obviously wrong, but that’s the direction I was trying… Am I being foolish, trying to use reduce, or can I just not code for toffee? Be gentle, please.

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  1. Editorial Team
    Editorial Team
    2026-05-31T00:02:17+00:00Added an answer on May 31, 2026 at 12:02 am

    A list comprehension will be more pythonic:

    >>> l = [1, 2, 3, 4, 10]
    >>> [y-x for x, y in zip(l, l[1:])]
    [1, 1, 1, 6]
    
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