Question

Define:

val x = List(1, 2, 3, 4)

I want to find if x contains either 1 or 3.
One way is

x.contains(1) || x.contains(3)

another is

x.exists(y => y == 1 || y == 3)

and another is:

x.exists(List(1,3).contains(_))

I would have preferred something similar to

x.containsAnyOf(1, 3)

Note that x.containsSlice does not work in this case.

Is there a better solution?

Answer 1

You can do

x exists Set(0, 1, 2)