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Home/ Questions/Q 8857549
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T14:37:00+00:00 2026-06-14T14:37:00+00:00

(defn square [x] (do (println (str Processing: x)) (* x x))) (println (map square

  • 0
(defn square [x]
  (do
    (println (str "Processing: " x))
    (* x x)))

(println (map square '(1 2 3 4 5)))

Why is the output

(Processing: 1 
Processing: 2 
1 Processing: 3 
4 Processing: 4 
9 Processing: 5 
16 25)

not

(Processing: 1
1 Processing: 2
4 Processing: 3 
9 Processing: 4 
16 Processing: 5 
25)

?

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  1. Editorial Team
    Editorial Team
    2026-06-14T14:37:01+00:00Added an answer on June 14, 2026 at 2:37 pm

    println uses [[x & xs] xs] destructuring form in its implementation. This is equivelent to [x (first xs), xs (next xs)] and next is less lazy than rest, so it realizes the two items before printing the first.

    For example,

    => (defn fn1 [[x & xs]] nil)
    #'user/fn1
    => (fn1 (map square '(1 2 3 4 5)))
    Processing: 1
    Processing: 2
    nil
    
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