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Home/ Questions/Q 7044743
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:26:46+00:00 2026-05-28T02:26:46+00:00

element on the page has needed content that i’m trying to pull here’s the

  • 0

element on the page has needed content that i’m trying to pull
here’s the element.content after a parse with Nokogiri

["\n       \n       \n       \n          itemId[0]=1234;\n       \n        \n          \n        \n       \n       \n       \n        My Project: First Edition\n       \n      ", "\n       \n       \n       \n          itemId[1]=2345;\n       \n        \n          \n        \n       \n       \n       \n        My Second Edition\n       \n      ", "\n       \n       \n       \n          itemId[2]=1234;\n       \n        \n          \n        \n       \n       \n       \n        Third\n       \n          \n"]

I was able to get the RegEx for the itemId[0]=1234 which is (/itemId.\d+..\d{4}/) but I’m totally stuck on how to grab the names of the content. Any advice? Perhaps I can just parse with Ruby through HTML?

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:26:46+00:00Added an answer on May 28, 2026 at 2:26 am

    Given a string like this:

    s= "\n       \n       \n       \n          itemId[0]=1234;\n       \n        \n          \n        \n       \n       \n       \n        My Project: First Edition\n       \n      "
    

    You could do this:

    m    = s.match(/(itemId\[\d+\]=\d+);(.*)/m)
    item = m[1]
    # itemId[0]=1234
    name = m[2].strip
    # My Project: First Edition
    

    Basically you pull out the itemId... part using (more or less) or existing expression, grab the rest of the string ((.*)) in multi-line mode (/m, so that . matches a newline), and then strip off the offending whitespace outside the regex using strip. You don’t have to build one unreadable regex that does everything you need, post-processing a match result is allowed and sometimes even encouraged.

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