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Home/ Questions/Q 7164847
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:08:35+00:00 2026-05-28T14:08:35+00:00

Example: <div> <div class=’drop’> <div class=’drag’></div> </div> <div class=’drop’> </div> <div class=’drop’> </div> <div

  • 0

Example:

<div>
    <div class='drop'>
        <div class='drag'></div>
    </div>
    <div class='drop'>
    </div>
    <div class='drop'>
    </div>
    <div class='drop'>
    </div>
    <div>
    </div>
</div>

$('div.drag').draggable({ containment: 'div.drop' });

Normally, if there is only 1 “div.drop” element, it works as intended. If there are more than 1(like in the example above), I thought that it would be dragged/dropped in any of the “div.drop” divs. As it turns out, it is only draggable/droppable to the first element matched by the “div.drop” selector.

Is there a workaround for this(that is, make it contained/droppable/draggable only in the “div.drop” divs)?

EDIT: I guess you are right guys. After some introspection, I realized that I didn’t go for your suggested solutions since there are padding between the divs and I don’t want the the “div.drag” divs to be dropped on the padded area.

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  1. Editorial Team
    Editorial Team
    2026-05-28T14:08:36+00:00Added an answer on May 28, 2026 at 2:08 pm

    It don’t works like that !!
    The containment is to constraint bound of dragging.

    You want drag and drop.
    Then you have to configure drag for div.grag:

    $('div.drag').draggable();
    

    And configure drop for div.drop:

    $('div.drop').droppable();
    

    You can add containment for your drag element with your first div level:

    <div id='dragZone'>
        <div class='drop'>
            <div class='drag'></div>
        </div>
        <div class='drop'>
        </div>
    </div>
    
    
    $('div.drag').draggable({ containment: '#dragZone'});
    
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