Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1087199
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T22:54:29+00:00 2026-05-16T22:54:29+00:00

final String json = \name\ : \john\ , \worth\ : \123,456\; String[] ss =

  • 0
final String json = "\"name\" : \"john\" , \"worth\" : \"123,456\"";    
String[] ss = json.split("\"\\s*,\\s*\"");
System.out.println(json);
for (String s : ss) {
    System.out.println("--> " + s);
}

The output is

"name" : "john" , "worth" : "123,456"
--> "name" : "john
--> worth" : "123,456"

Is there any way I can get

"name" : "john" , "worth" : "123,456"
--> "name" : "john"
--> "worth" : "123,456"
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T22:54:29+00:00Added an answer on May 16, 2026 at 10:54 pm

    Using Regex

    While I must agree that using a JSON parser makes a lot more sense, even if you want to use regex, String.split() is not the right tool. Use a Pattern and a Matcher:

    final String json = "\"name\" : \"john\" , \"worth\" : \"123,456\"";
    final Pattern pattern =
        Pattern.compile("\"(.*?)\"\\s*:\\s*\"(.*?)\"", Pattern.DOTALL);
    final Matcher matcher = pattern.matcher(json);
    while(matcher.find()){
        System.out.println(matcher.group(1) + ":" + matcher.group(2));
    }
    

    Output:

    name:john
    worth:123,456
    

    And if you really want to retrieve the quotes, change the pattern to

    final Pattern pattern =
        Pattern.compile("(\".*?\")\\s*:\\s*(\".*?\")", Pattern.DOTALL);
    

    Output:

    "name":"john"
    "worth":"123,456"
    

    Of course this won’t help with different JSON structures like nested object structures, arrays, primitives etc.


    Using JSON parsers

    But if your question is just about how to do this with JSON parsers, here is an example using JSONObject:

    final String json = "{\"name\" : \"john\" , \"worth\" : \"123,456\"}";
    final JSONObject jsonObject = new JSONObject(json);
    @SuppressWarnings("unchecked")
    final Iterator<String> it = jsonObject.keys();
    while(it.hasNext()){
        final String nextKey = it.next();
        System.out.println(nextKey + ":" + jsonObject.getString(nextKey));
    }
    

    No classes needed. Output:

    name:john
    worth:123,456
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Say I have class A with class A { final String foo() { //
Consider the following interface in Java: public interface I { public final String KEY
I launch a child process in Java as follows: final String[] cmd = {<childProcessName>};
I'm trying to pass the following String to a PreparedStatement : private static final
When I pass an immutable type object(String, Integer,.. ) as final to a method
I'm still pretty new to JSON and GWT and I'm trying to figure out
Final question for the night. And apologies for the complete noobness of this. I
While in the final throws of upgrading MS-SQL Server 2005 Express Edition to MS-SQL
public static Logger getLogger() { final Throwable t = new Throwable(); final StackTraceElement methodCaller
I'm on the final stretch of my first simple iPhone application. I'm building an

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.