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Editorial Team
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Asked: 2026-06-11T15:25:29+00:00

Following code doesn’t throw exception and prints success. Why ? #include <iostream> int main()

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Following code doesn’t throw exception and prints “success”. Why ?

#include <iostream>

int main() 
{
    size_t size = size_t(1024)*1024*1024*1024*1024*1024*1024*1024;
    char* data = new char[size];

    if (data == NULL)
        std::cout << "fail" << std::endl;
    else
        std::cout << "success" << std::endl;

    return 0;
}
  • Compiler: g++ (Ubuntu/Linaro 4.6.3-1ubuntu5) 4.6.3
  • OS: Ubuntu 12.04
  • RAM: 8 GB

And if this is how it’s meant to work, how do I check that I have enough memory ?

[Edit: made my stupid code a bit more correct, now it would at least fail on x64 if I remove two *1024]

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1 Answer

  1. Editorial Team

    My compiler can answer this one:

    $ g++ --version
g++ (GCC) 4.7.1 20120721 (prerelease)
Copyright (C) 2012 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

$ g++ -Wall -Wextra -pedantic q12507456.c++
q12507456.c++: In function 'int main()':
q12507456.c++:5:42: warning: integer overflow in expression [-Woverflow]
$
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