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Home/ Questions/Q 3344846
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T01:07:00+00:00 2026-05-18T01:07:00+00:00

Following on from this question regarding calculating a member I have 2 calculated members

  • 0

Following on from this question regarding calculating a member I have 2 calculated members defined as:

MEMBER [Asset].[Class].[Fixed Income Derivatives]
AS
AGGREGATE(
    {
       [Asset].[Class].&[Fixed Income],
       [Asset].[Sub Class].&[Derivatives]
    },
    [Measures].CurrentMember
)
MEMBER [Asset].[Class].[Fixed Income Non-derivatives]
AS
AGGREGATE(
    {
      [Asset].[Class].&[Fixed Income],
      EXCEPT([Asset].[Sub Class].[Sub Class],[Asset].[Sub Class].&[Derivatives])
    },
    [Measures].CurrentMember
)

I can use these in an MDX query as follows:

SELECT
  {
   [Measures].[Market Value]
  } ON 0,
  NON EMPTY
  { 
   [Asset].[Class].[Fixed Income Derivatives],
   [Asset].[Class].[Fixed Income Non-derivatives]
   [Asset].[Class].[Class]
  } ON 1
  FROM [Asset]

And this gives me output as follows:

Class-----------------------|-MarketValue
============================|=============
Fixed Income Derivatives    | 12345
Fixed Income Non-derivatives| 54321
Fixed Income                | 66666
Property                    | 123
Equity                      | 987

Note that the first 2 rows are actually constituant parts of Row 3. Now, I can do some magic with the client code which reads this data to turn that table into a hierarchy, but – and here’s the question – can I do it using MDX? Or am I just complicating things? Im not adverse to making changes in the cube if necessary, or if I could define this hierarchy there.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T01:07:01+00:00Added an answer on May 18, 2026 at 1:07 am

    I ended up just returning both Class and Sub Class, and building the hierarchy in client code.

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