"foo\r\nbar".replace(/(foo).+/m, "bar")
Hello. I can not understand why this code does not replace foo on bar
foo\r\nbar.replace(/(foo).+/m, bar) Hello. I can not understand why this code does not replace foo
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"foo\r\nbar".replace(/(foo).+/m, "bar")
Hello. I can not understand why this code does not replace foo on bar
Because the dot
.explicitly does not match newline characters.This would work:
because newline characters count as whitespace (
\s).Note that the parentheses around
fooare superfluous, grouping has no benefits here.