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Home/ Questions/Q 8756681
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T14:08:07+00:00 2026-06-13T14:08:07+00:00

For example, there’re two similar codes: The first one is: for chrom in bins:

  • 0

For example, there’re two similar codes:

The first one is:

 for chrom in bins:
     for a_bin in bins[chrom]:
         for pos in a_bin:
             pos = pos+100

The second one is:

 for chrom in bins:
     for a_bin in bins[chrom]:
         for pos in a_bin:
             if chrom=="chr1":
                 pos = pos*100

I was wondering that whether there’s a way to refactor the loop so that I don’t need to repeat writing code with the same structure..

Anyone has ideas about this?

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  1. Editorial Team
    Editorial Team
    2026-06-13T14:08:08+00:00Added an answer on June 13, 2026 at 2:08 pm

    This can be achieved with a generator function.

    def gen():
        for chrom in bins:
            for a_bin in bins[chrom]:
               for pos in a_bin:
                   yield pos
    

    You can iterate through the items generated by gen(), though there is no “list of item” that is built — rather, it is constructed on demand:

    for pos in gen():
        pass # add loop code here
    

    This also means that, if you exit the loop early, the gen() method will be aborted (with an exception). Take a look at corutines to understand how this is implemented.

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