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Home/ Questions/Q 899575
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T15:14:29+00:00 2026-05-15T15:14:29+00:00

For some reason, I can’t seem to find a good answer for this one.

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For some reason, I can’t seem to find a good answer for this one.

I have been trying to escape out the caret (\^), and to use the hex, octal, and other codes for the character using \xdd, \dddd, etc…

But my replace regexp won’t replace the caret (^) with anything. It seems to simply break the expression.

Here is the code I am using:


var field,myExp;    

// \x5E is supposed to represent the caret in Hex...
    myExp = / *[^a-z^A-Z^0-9\s\x5E]/gi;

field = field.replace(myExp,"");
alert(field);

Help!

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  1. Editorial Team
    Editorial Team
    2026-05-15T15:14:29+00:00Added an answer on May 15, 2026 at 3:14 pm

    I found the answer, but you guys all helped me get there. Thanks!

    I think what was happening was that my exlude (^) was used too many times and so was creating an exclusion of my exclusionary groups… Since there were no separators between the groups, the first one does the trick.

    ORIGINAL:
    repExp = / *[^a-z^A-Z^0-9]/gi;

    FINAL REGEXP:
    repExp = / *[^a-zA-Z0-9]/gi;

    The above filters out anything that is not a leter (a-zA-Z) or number (0-9) from a string.

    Thanks, people!

    P.S. The space after the initial “/” is there because for some reason, Dreamweaver sees it as the beginning of a comment. 🙁

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