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Home/ Questions/Q 1012753
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T09:59:37+00:00 2026-05-16T09:59:37+00:00

For some reason, YQL’s XSLT table can’t parse my stylesheet. I have used the

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For some reason, YQL’s XSLT table can’t parse my stylesheet. I have used the stylesheet successfully with the W3C’s XSLT service. Here’s an example of the problem in YQL Console. Why does this not work in YQL?

Also, I have yet to figure out how to pass the results of a YQL query to the XSLT table as the XML to be transformed while also specifying a stylesheet url. Current workaround is to abuse the W3C’s service.

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  1. Editorial Team
    Editorial Team
    2026-05-16T09:59:38+00:00Added an answer on May 16, 2026 at 9:59 am

    Your stylesheet is defined as 1.0 but you’re using replace() and tokenize() which is part of the 2.0 standard. However it is a fully valid XSLT/XPath 2.0 stylesheet.

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