Question

from my ksh I have

  [[  ` echo $READ_LINE | awk '{print $2}' ` != SOME_WORD  ]] && print "not match"

can I get suggestion how to verify the same without echo command? ( maybe awk/sed is fine for this? )

lidia

Answer 1

Something like this will work:

awk -v x="$READ_LINE" -v y="SOME_WORD" 'BEGIN { split(x, a); if (a[2] != y) print "not match";}'

But where does $READ_LINE come from? What are you trying to accomplish? There might just also is a good plain sh or ksh solution.

I highly doubt your claim that echo (which might be a shell builtin) takes more time than awk. Here is a plain sh version:

set -- $READ_LINE
[ x$2 != xSOME_WORD] && echo "not match" 

But the ksh solution of Dennis Williamson looks the best for your situation.