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Home/ Questions/Q 430617
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T19:53:34+00:00 2026-05-12T19:53:34+00:00

From the Wikipedia article on Read-Copy-Update : The reason that it is safe to

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From the Wikipedia article on Read-Copy-Update:

The reason that it is safe to run the removal phase concurrently with readers is the semantics of modern CPUs guarantee that readers will see either the old or the new version of the data structure rather than a partially updated reference.

Is this true for all modern CPUs (ARM, x86, PPC, etc.)? Is it likely to change in the future? It seems awfully nice to never need to pay the cost of doing a locked load so long as you don’t mind possibly getting the old value again (this probably isn’t an issue for many applications — basically for any app that could use read-copy-update).

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  1. Editorial Team
    Editorial Team
    2026-05-12T19:53:35+00:00Added an answer on May 12, 2026 at 7:53 pm

    Well if you use primitive types with size <= databus size and the data is aligned properly then it is true. So it more depends on your code then on a modern cpu.

    You can assume that this will continue to exist because it is impossible to write a garbage collector if there can be partial updated pointers. And using lock prefixes around each single pointer access would kill performance totally.

    So yes, the article is correct (again assuming size and alignment).

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