Question

FromIp contains '192.168.1.1'. I want to get the last number, but I can’t figure out what’s wrong here:

     Dim str As String     str = FromIP.Text.Substring(FromIP.Text.LastIndexOf('.'), FromIP.Text.Length).ToString()     MessageBox.Show(FromIP.Text.Length) 

Answer 1

Tested code:

    Dim FromIp As String = '192.168.1.1'     Dim str As String     str = FromIp.Substring(FromIp.LastIndexOf('.') + 1).ToString()     MessageBox.Show(str) 

• You must add 1 to LastIndexOf to skip the dot
• There no need put the lenght of the Substring when you want all the rest of the string

But this refactored code will work better:

    Dim FromIp As String = '192.168.1.1'     Dim IpPart As String() = FromIp.Split('.')     MessageBox.Show(IpPart(3))