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Home/ Questions/Q 7921453
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T16:35:25+00:00 2026-06-03T16:35:25+00:00

$(function(){ $(.square).toggle( function(){ $(this).animate({width:200px}, 900); }, function(){ $(this).animate({width:100px}, 900); } ); $(document).click(function() { $(‘.square’).animate({

  • 0
$(function(){ 
    $(".square").toggle(
        function(){ $(this).animate({"width":"200px"}, 900); 
                  },

        function(){ $(this).animate({"width":"100px"}, 900); 
        } 
    ); 

    $(document).click(function() {
       $('.square').animate({ "width":"100px"}, 900);  
    });
})​

In this example,
1- The user click the square once (the first function of the toggle is executed).
2- The user then click the background another function is called
3- The user click back the square (and I suppose the second function of the toggle is called, that does the same that the num. 2 and that is why nothing happens in the first click.)

So I suppose in the num. 2 I should skip all the toggle function. I don’t know how to do it

How to skip all the toggle if only the first function is executed?

(by the way I tried “stop().animate” and it doesn’t work)

Here is the example working. You can make changes: http://jsfiddle.net/xngx9/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T16:35:27+00:00Added an answer on June 3, 2026 at 4:35 pm

    demo

    $(function(){
        $(".square").click(function(e){
            e.stopPropagation();
            var tgl = $(this).width() === 100 ?
            $(this).stop(1).animate({"width":"200px"}, 900):
            $(this).stop(1).animate({"width":"100px"}, 900);
        });
    
        $(document).click(function() {
          $('.square').stop(1).animate({ "width":"100px"}, 900);  
        });
    });
    
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