Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 570637
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T13:25:23+00:00 2026-05-13T13:25:23+00:00

gcc c89 I am came across this code. typedef __int32 int32_t; typedef unsigned __int32

  • 0

gcc c89

I am came across this code.

typedef __int32 int32_t;
typedef unsigned __int32 uint32_t;
typedef __int64 int64_t;
typedef unsigned __int32 uint64_t;

I am just wondering that is the __int32 I didn’t think that was a type? Why the underscore?

Does this mean I could do things like this?

typedef __int32 myInt32;

Many thanks for any advice,

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T13:25:23+00:00Added an answer on May 13, 2026 at 1:25 pm

    The type is not standard, but is supported on your compiler.

    Symbols that begin with an underscore or contain two underscores are reserved by the standard for your compiler’s implementation.

    See Why do people use __(double underscore) so much in C++ (The question is about C++ but the reason is the same)

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

gcc (GCC) 4.6.3 c89 Hello, I am just wondering if this is the best
gcc 4.4.2 c89 I have this code snippet that I have to repeat in
I'm just wondering whether this is good code for a C89 program. obj_ptr =
gcc 4.6.2 c89 I am just wondering if this is a good way to
gcc c89 I am just looking to link against the below shared library. I
gcc (GCC) 4.6.3 c89 apache runtime portable libraries Hello, Just a simple question I
gcc 4.4.3 c89 I am just getting started with log4c. However, there is very
gcc 4.4.4 c89 I was just experimenting with a int array. And something just
gcc 4.4.1 c89 I have the following code snippet: #include <stdlib.h> #include <stdio.h> char
gcc 4.4.1 c89 I have the following code: static enum states { ACTIVE, RUNNING,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.