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Home/ Questions/Q 8969459
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T17:35:38+00:00 2026-06-15T17:35:38+00:00

Given an type involving type variables, is there a way to defined an infinite

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Given an type involving type variables, is there a way to defined an infinite list of type variables in which no type variable are ever repeated?

Let me provide more context with my question. I’m working on a type inference of my own in Haskell. My data type looks like this:

data Ty = TyUnit
        | TyVar String
        | TyBool
        | TyInt
        | TyBoolList
        | TyIntList
        | Arrow Ty Ty

I gave the definition of the type above. I believe that the function is supposed to generate an infinite list of variable names. I’m just confused on how to proceed and the actual implementation of the question.

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  1. Editorial Team
    Editorial Team
    2026-06-15T17:35:39+00:00Added an answer on June 15, 2026 at 5:35 pm

    Here you go.

    allTys 0 = TyUnit : TyVar "?" : TyBool : TyInt : TyBoolList :  TyIntList : []
    allTys n = [0..n-1] >>= (\i -> liftM2 Arrow (allTys i) (allTys (n-1-i))) 
    
    allTypes = [0..] >>= allTys
    

    allTys n constructs a type tree of height n. Here height of Arrow x y is height of x + height of y + 1 and height of everything else is 0. The construction is very basic. I’m not sure if it can be done faster. Ask in the comments, if it needs more explaining.

    Also, in case that is needed, this is how to get all strings of an alphabet (say ['a'..'z']) .

    strings alphabet = (:) [] $ liftM2 (flip (:)) (strings alphabet) alphabet
    

    The idea that a long string is a somechar:shortstring. Note that the empty string is included.

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