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Home/ Questions/Q 8010629
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Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T18:47:49+00:00 2026-06-04T18:47:49+00:00

Given I have the function: void A::IAmCool(int x, …) { va_list args; va_start (args,

  • 0

Given I have the function:

void A::IAmCool(int x, ...)
{
        va_list args; 
        va_start (args, x);   
        va_end (args);
}

How do I pass var-args from one function to another? I’m looking for something like this:

void A::extractedFunction() /* this doesn't work */
{
        va_list args; 
        va_start (args, ?????);   
        va_end (args);
}

void A::IAmCool(int x, ...)
{
        extractedFunction();
}

Is this even possible? I have tried making the function inline but that doesn’t work.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T18:47:51+00:00Added an answer on June 4, 2026 at 6:47 pm

    The usual pattern is to implement your main workhorse function taking a valist, and the variadic function only as “decoration”. Then you can use the main function directly from third-party call sites. Example:

    #include <cstdarg>
    
    int vgizmo(int a, std::va_list ap)
    {
        // main implementation here!
    }
    
    int gizmo(int a, ...)  // interface function
    {
        std::va_list ap;
        va_start(ap, a);
        int r = vgizmo(a, ap);
        va_end(ap);
        return r;
    }
    
    void some_other_stuff(bool q, char const * fmt, ...)
    {
        std::va_list ap;
        va_start(ap, fmt);
    
        // ...
    
        int b = vgizmo(x, ap);   // third parties use vgizmo directly
    
        // ...
    
        va_end(ap);
    }
    
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