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Home/ Questions/Q 7768557
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:56:39+00:00 2026-06-01T15:56:39+00:00

Given the following code: var a = ‘somegarbage=http://somesite.com/foo/bar/&moregarbage’; var result = a.match(/http.+\//g); Produces the

  • 0

Given the following code:

var a = 'somegarbage=http://somesite.com/foo/bar/&moregarbage';
var result = a.match(/http.+\//g);

Produces the expected result: ["http://somesite.com/foo/bar/"]

Now, if I do this:

var a = 'somegarbage=http://somesite.com/foo/bar/&moregarbage';
var config = JSON.parse('{"filter":"/http.+\\//g"}'); //notice the extra '\'?
var result = a.match(config.filter);

It returns null. I presume that it has to do with the string escaping of \ in JSON. I feel like I’m missing a simple solution. How can I fix this? Thanks.

Edit:

I have also tried this and it doesn’t work:

var a = 'somegarbage=http://somesite.com/foo/bar/&moregarbage';
var config = JSON.parse('{"filter":"/http.+\\//g"}'); //notice the extra '\'?
var result = a.match(new RegExp(config.filter));
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T15:56:40+00:00Added an answer on June 1, 2026 at 3:56 pm

    JSON doesn’t accept regular expressions as a type. So, you need to just put the regular expression in a string (with the leading / and trailing / and then after you parse it, you need to feed the regular expression to new RegExp(str) to turn it into a regular expresssion.

    You can do it like this:

    var a = 'somegarbage=http://somesite.com/foo/bar/&moregarbage';
    var x = JSON.parse('{"filter":"http.+/", "flags": "g"}');
    x.filter = new RegExp(x.filter, x.flags);
    var result = a.match(x.filter);
    alert(result);​
    

    Working example here: http://jsfiddle.net/jfriend00/5pa2j/

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