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Home/ Questions/Q 7539551
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T07:24:47+00:00 2026-05-30T07:24:47+00:00

Given the following two queries, which one would be faster (in theory) if there

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Given the following two queries, which one would be faster (in theory) if there is any difference at all.

SELECT `ViewCounterView`.`id`, `ViewCounterView`.`referer`, 
(COUNT(`ViewCounterView`.`id`)) AS `ViewCounterView__referer_count`, 
(LOCATE("http", `ViewCounterView`.`referer`) >= 1) AS `ViewCounterView__external` 
FROM `dogmatic69`.`view_counter_views` AS `ViewCounterView` 
WHERE `ViewCounterView`.`referer` IS NOT NULL 
GROUP BY `ViewCounterView`.`referer` 
ORDER BY (LOCATE("http", `ViewCounterView`.`referer`) >= 1) desc 
LIMIT 20

or

SELECT `ViewCounterView`.`id`, `ViewCounterView`.`referer`, 
(COUNT(`ViewCounterView`.`id`)) AS `ViewCounterView__referer_count`, 
(LOCATE("http", `ViewCounterView`.`referer`) >= 1) AS `ViewCounterView__external` 
FROM `dogmatic69`.`view_counter_views` AS `ViewCounterView` 
WHERE `ViewCounterView`.`referer` IS NOT NULL 
GROUP BY `ViewCounterView`.`referer` 
ORDER BY ViewCounterView__referer_count desc 
LIMIT 20

Difference being in the ORDER BY. In the first instance would MySQL know the fragment is being repeated and not calculate again, or in the second one does it use the alias to get the fragment and recalculate the value?

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  1. Editorial Team
    Editorial Team
    2026-05-30T07:24:49+00:00Added an answer on May 30, 2026 at 7:24 am

    There is no difference: MySQL will calculate the value only once per row. As you do it in the field definition, it is already done.

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