Question

Hello i am trying to return a struct from a function but i cant find a way to do so without declaring the struct as global. How can this be done? Here is the code (THIS WORKS AS IT IS)

...
void log_in();
struct node
{
    char name_log[20];
    int passlog;
    int user_point;
}tmp;

int main()
{
  ...
  else if(sel=='2')
  {
     log_in();
     if (tmp.passlog==TRUE)
     logged_in(tmp.name_log,tmp.user_point);  //and here i want to use the retun values
  }

void log_in()
{
   ... //make the changes in the struct
}
...

What i want to achieve is to place the struct node declaration within main but sadly it wont work. So here is what i am trying to do: (THIS DOESN’T WORK)

...
struct node log_in();

int main() {
    ...
    else if(sel=='2') {
        struct node //here is where i want to declare
        {
            char name_log[20];
            int passlog;
            int user_point;
        }tmp;

        log_in();
        if (tmp.passlog==TRUE)
            logged_in(tmp.name_log,tmp.user_point); //and here i want to use the retun values
    }

    struct node log_in()
    {
        ...
        return tmp;
    }
    ...

Answer 1

 else if(sel=='2')            //or within this block but I don't know how.
  {  struct node tmp;
     tmp=log_in();
     if (tmp.passlog==TRUE)
     logged_in(tmp.name_log,tmp.user_point);  //and here I want to use the return values
  }

and inside the function log_in()

struct node log_in()
{ 
 struct tmp
 ...
 return tmp;
}

use a local variable inside the function and return this variable. Assign it to another variable inside main().