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Home/ Questions/Q 9214193
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T01:55:21+00:00 2026-06-18T01:55:21+00:00

Help! I’m doing a replace that will convert a bracketed block to a block

  • 0

Help! I’m doing a replace that will convert a bracketed block to a block surrounded by <div>s. Please see below.

The code:

$data = '
<p>
{ 
asdf
asdf
asdf
}
</p>
';

echo preg_replace('%{(.*)}%m', '<div>\1</div>', $data);

The output should be:

<p>
<div>
asdf
asdf
asdf
</div>
</p>

What am I doing wrong here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T01:55:23+00:00Added an answer on June 18, 2026 at 1:55 am

    Use the s modifier instead of the m modifier.

    The s modifier allows . to match newlines.

    The m modifier makes ^ and $ match the start and end of individual lines, as opposed to the start and end of the entire string.

    Side-note: The preferred syntax for the replacement is <div>$1</div>

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