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Home/ Questions/Q 922809
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Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T19:05:33+00:00 2026-05-15T19:05:33+00:00

Here I am trying to route a page without showing its action in URL,

  • 0

Here I am trying to route a page without showing its action in URL,

Eg: URL is http://localhost/brands/1/xyz

Router::connect(
    '/brands/:id/:name',
    array(
        'controller' => 'brands',
        'action' => 'index',
        'id' => '[0-9]{1,}',
        'name' => '[a-z]{1,}'
    )
);

it works fine….

But I need to make the id and name as optional and tried this:

Router::connect(
    '/brands/:id/:name',
    array(
        'controller' => 'brands',
        'action' => 'index',
        'id' => '[0-9]{1,}',
        'name' => '[a-z]{1,}'
    )
);

according to http://book.cakephp.org/view/542/Defining-Routes

But when I try this URL http://localhost/brands/1 it searches for action 1 but http://localhost/brands/1/xyz works fine.

Is there any mistake in my routing configuration????

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:05:33+00:00Added an answer on May 15, 2026 at 7:05 pm

    If you just want to be able to access the http://localhost/brands/1, you need to add this route:

    Router::connect('/brands/:id',
       array('controller' => 'brands','action' => 'index','id' => '[0-9]{1,}')
    );
    

    (and also keep your original route)

    Router::connect('/brands/:id/:name',
        array('controller' => 'brands','action' => 'index','id' => '[0-9]{1,}','name' => '[a-z]{1,}')
    );
    

    (and finally a route for /brands)

    Router::connect('/brands',
        array('controller' => 'brands','action' => 'index')
    );
    

    Then check for $this->params[‘id’] and $this->params[‘name’] in the controller. If needed, redirect to the correct url (if the page is the same and you always want to have the the name in the url, which is good for SEO).

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