Question

here is my problem.
I have thousands lines like followed to convert.
Can I solve it with regular expression?

Original:

beSendToTheSpecialCustomer = new BooleanElement("SendToTheSpecialCustomer",false);

to:

beSendToTheSpecialCustomer = new BooleanElement("Send To The Special Customer",false);

Thanks for any suggestion.

Edited:
I just found a not-perfect solution to this in np++

find:

(\".*)([a-z])([A-Z])(.*\")

replace with:

\1\2 \3\4

then click “replace all”, but that just replace one word in every line each time, so I need click several times to replace all words, but I can finish my job in 1 minute.

Better solution from Placido
find:

([a-z])([A-Z])(?=[^()]+,(?:false|true)\);)

replace with:

\1 \2

Answer 1

I’m afraid you can’t do it with Np++ only. But this can be easily done with callback using almost any programming language. For example with PHP:

$txt = 'beSendToTheSpecialCustomer = new BooleanElement("Send To The Special Customer",false);';
echo preg_replace_callback('/new\s+\w+\s*\(\s*"(\w+)"\s*,\s*\w+\s*\)/', 
    function($match){
        return preg_replace('/([a-z])([A-Z])/', '\1 \2', $match[1]);
    },
    $txt
);

---

Edit:

Here is a non-perfect solution using regular expressions in Notepad++:

Find

([a-z])([A-Z])(?=[^()]+,(?:false|true)\);)

Replace with

\1 \2