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Home/ Questions/Q 830441
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:02:39+00:00 2026-05-15T04:02:39+00:00

Here is the the function and the globals: $note_instance = Array(); $note_count = 0;

  • 0

Here is the the function and the globals:

      $note_instance = Array();
      $note_count = 0;

      function create(text){
        count = $note_count++;

        time = 5000;            

        $note_instance[count] = $notifications.notify("create", text);

        setTimeout(function(){ $note_instance[count].close() }, time);
      }

The function simply opens a notification, a sets a timeout to close it in 5 seconds.

so if i call this

 create("Good Note 1");
 create("Good Note 2");
 create("Good Note 3");

Ecah note should close 5 seconds from their creation, however always and only the last note closes, in this case “Good Note 3”.

Each note object has its own entry in the the $note_instance global array so the timeouts should no be overwriting themselves.

What am i missing here folks? Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-05-15T04:02:40+00:00Added an answer on May 15, 2026 at 4:02 am

    count is a global variable.

    You need to change it to a local variable by adding var count inside the function.

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