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Home/ Questions/Q 6361421
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:46:31+00:00 2026-05-24T23:46:31+00:00

Here my function that i try to trasform dates into different formats. /* example:

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Here my function that i try to trasform dates into different formats.

/*  example:
*   dateString          =   '03/25/2010';
*   inputDateFormat     =   '%m/%d/%Y';
*   ouputDateFormat     =   'Y-m-d';
*   return              ->  '2010-03-25';
*/  
function formatDate($dateString,$inputFormat=NULL,$outputFormat=NULL){
    if($dateString==''||$dateString==NULL) return '';
    $t =  strptime($dateString,$inputFormat);
    return gmdate($outputFormat,mktime($t[tm_sec],$t[tm_min],$t[tm_hour],($t[tm_mon]+1),($t[tm_mday]+1),($t[tm_year]+1900)));
}

My problem is

when i try to convert this date Wed, 19 Jan 2011 21:16:37 +0000 into 2011-01-19 21:16:37 with the following line:

echo formatDate('Wed, 19 Jan 2011 21:16:37 +0000','%a, %d %b %Y %H:%M:%S','Y-m-d H:i:s');

the result is this:

2011-01-21 11:16:21

why i’m getting the date with 2 days extra.
Do you have any idea?

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:46:31+00:00Added an answer on May 24, 2026 at 11:46 pm

    use this instead:

      function formatDate($dateString, $outputFormat=NULL){
          return date($outputFormat, strtotime($dateString));
      }
    
      echo formatDate('Wed, 19 Jan 2011 21:16:37 +0000','Y-m-d H:i:s');
    
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