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Home/ Questions/Q 7659871
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:23:23+00:00 2026-05-31T13:23:23+00:00

Here’s the faulty bit of my code: class Room(object): def __init__(self): self.hotspots = []

  • 0

Here’s the faulty bit of my code:

class Room(object):
    def __init__(self):
        self.hotspots = []
        self.image = []
        self.item = []

    def newhotspot(*args):
        new = {'Name' : None,
               'id' : None,
               'rect' : None,
               'Takeable' : None,
               'Lookable' : None,
               'Speakable' : None,
               'Itemable' : None,
               'Goable' : None}

        for i in args:
            new[i[0]] = i[1]
        new['id'] = len(self.hotspots)
        self.hotspots.append(new)

CityTrader = Room()

CityTrader.newhotspot(('Name', 'Trader'),
                      ('Takeable', 'Yes'))

The goal is to have a dictionary with all the keys set to none but the ones specified.
However, when I run it I get:

[...]line 85 in <module>
('Takeable', 'Yes'))
[...]line 44, in newhotspot
new[i[0]] = i[1]
TypeError : 'Room' object does not support indexing

Anyone knows why and how to solve this?
It seems to work when it’s not wrapped inside a class.

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:23:24+00:00Added an answer on May 31, 2026 at 1:23 pm

    You forgot the self parameter to newhotspot():

    def newhotspot(self, *args):
        ...
    

    Since self will be implicitly passed anyway, it ends up as the first item of args.

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