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Home/ Questions/Q 687919
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T02:10:35+00:00 2026-05-14T02:10:35+00:00

Here’s what I’ve got so far: # A. match_ends # Given a list of

  • 0

Here’s what I’ve got so far:

# A. match_ends
# Given a list of strings, return the count of the number of
# strings where the string length is 2 or more and the first
# and last chars of the string are the same.
# Note: python does not have a ++ operator, but += works.
def match_ends(words):
  counter = 0
  for word in words:
    if len(word) >= 2 and word[0] == word[-1]:
      counter += counter
  return counter
  # +++your code here+++
  return

I’m following the Google Python Class, so this isn’t homework, but me just learning and improving myself; so please no negative comments about ‘not doing my homework’. 😛

What do you guys think I’m doing wrong here?

Here’s the result:

match_ends
  X  got: 0 expected: 3
  X  got: 0 expected: 2
  X  got: 0 expected: 1

I’m really loving Python, so I just know that I’ll get better at it. 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-14T02:10:36+00:00Added an answer on May 14, 2026 at 2:10 am

    You should do:

    counter += 1
    

    instead of

    counter += counter
    

    which stays at 0 for all ages.

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