Question

Hi
I am using XSLT 1.0. My input looks like,

<table>
<tr>
  <td/>
  <td/>
  <td/>
</tr>
<tr>
  <td/>
  <td/>
  <td/>
</tr>
<tr>
  <td/>
  <td/>
  <td/>
  <td/>
</tr>
</table>

I want to know the maximum number of td in node. In this case, the maximum number of td is in 3rd tr and so my output should be 4. Need a template to do this. Thanks in advance

Answer 1

You need to use recursion. Basically, the running-max template listed below runs for every tr child element of a table. It is first applied for the first child tr element, calculates the number of td elements, compares it to a running max, and then continues to do the same for following siblings, if there are any.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

  <xsl:template match="/">
    <xsl:variable name="count">
      <xsl:apply-templates select="table"/>
    </xsl:variable>
  </xsl:template>

  <xsl:template match="table">
    <xsl:apply-templates select="tr[1]" mode="running-max"/>
  </xsl:template>

  <xsl:template match="tr" mode="running-max">
    <xsl:param name="max" select="'0'"/>
    <xsl:variable name="size" select="count(td)"/>
    <xsl:variable name="newmax">
      <xsl:choose>
        <xsl:when test="$size &gt; $max">
          <xsl:value-of select="$size"/>
        </xsl:when>
        <xsl:otherwise>
          <xsl:value-of select="$max"/>
        </xsl:otherwise>
      </xsl:choose>
    </xsl:variable>
    <xsl:choose>
      <xsl:when test="following-sibling::tr">
        <xsl:apply-templates select="following-sibling::tr[position()=1]" mode="running-max">
          <xsl:with-param name="max" select="$newmax"/>
        </xsl:apply-templates>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="$newmax"/>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>

</xsl:stylesheet>