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Hi
I have a question that:
consider I have T(n) = m * n^2 (n<m)
is this correct to write T(n) = O(m) ? because I have written T(n) = m*n*n So because n<m we have T(n) = O(m)
thanks
No, the best thing you can do is to write
T(n,m) = O(m^3).n < mis a very weak condition and basically just gives youn in O(m). For example, n could always bem-1.Edit: My first answer was imprecise, as T was only a function in n. If m is constant, the answer is still holds, but O(m^3) is equal to O(1).