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Home/ Questions/Q 9109261
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T03:00:07+00:00 2026-06-17T03:00:07+00:00

How can I get a property from the parent node of a media item

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How can I get a property from the parent node of a media item using “umbraco.library:GetMedia”?

This allows me to get the current nodes “@nodeName”

<xsl:value-of select="umbraco.library:GetMedia(., 0)/@nodeName" />

I want to get the parent of the current nodes “@nodeName”, I’ve tried the following but it doesn’t work:

<xsl:value-of select="umbraco.library:GetMedia(., 0)/../@nodeName" />

Can anyone help me out?

Cheers, JV

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T03:00:08+00:00Added an answer on June 17, 2026 at 3:00 am

    With a call to GetMedia() and the @parentID attribute in a variable, I’ve got it working using the following:

    <xsl:template match="/">
            <!-- Do not call unless an image was picked -->
            <xsl:apply-templates select="$currentPage/image[normalize-space()]" />
    </xsl:template>
    
    <xsl:template match="image">
            <!-- Note: These WILL fail if no media is selected -->
            <xsl:variable name="mediaNode" select="umbraco.library:GetMedia(., false())" />
            <xsl:variable name="parentMedia" select="umbraco.library:GetMedia($mediaNode/@parentID, false())" />
    
            <p>
                    Media: <xsl:value-of select="$mediaNode/@nodeName" />
            </p>
            <p>
                    Parent: <xsl:value-of select="$parentMedia/@nodeName" />
            </p>
    </xsl:template>
    
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